Zbigniew Jędrzejewski-Szmek
a9899ff358
We'd proceed rather inefficiently: the initial buffer size was LINE_MAX/2, i.e. only 1k. We can read 4k at the same cost. Also, we'd try to allocate 1025, 2049, 4097 bytes, i.e. always one higher than the power-of-two size. Effectively the allocation would be bigger, and we'd waste the additional space. So let's allocate aligned to the power-of-two size. size=4095, 8191, 16383, so we allocate 4k, 8k, 16k.
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